110=16t^2+85t+4

Solution for 110=16t^2+85t+4 equation:

110=16t^2+85t+4

We move all terms to the left:

110-(16t^2+85t+4)=0

We get rid of parentheses

-16t^2-85t-4+110=0

We add all the numbers together, and all the variables

-16t^2-85t+106=0

a = -16; b = -85; c = +106;
Δ = b2-4ac
Δ = -852-4·(-16)·106
Δ = 14009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-\sqrt{14009}}{2*-16}=\frac{85-\sqrt{14009}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+\sqrt{14009}}{2*-16}=\frac{85+\sqrt{14009}}{-32}
$